Show that if d > 2n/3, then A(n, d) = 2.
Analyze the show that if d > 2n/3, then a(n, d) = 2..
Examples
Input: "test_input_1"
Output: "output_1"
Input: "test_input_2"
Output: "output_2"
Hints
Consider the maximum number of edges in a graph with `n` vertices where each vertex has degree at least `d`. How does this relate to the given condition `d > 2n/3`?
Explore the relationship between the degree condition and the graph's connectivity. Can you construct a graph that violates the condition or prove it must satisfy `a(n, d) = 2`?
Use combinatorial arguments or extremal graph theory to show that any graph with `d > 2n/3` must have a specific structure (e.g., a dominating vertex or a near-complete graph), forcing the number of valid configurations to be exactly 2.
Show that if d > 2n/3, then A(n, d) = 2.
Analyze the show that if d > 2n/3, then a(n, d) = 2..